to find the volume occupied by 2.0 g of CS₂ gas we can use the ideal gas law equation PV = nRT where P - pressure - 726 mmHg x 133 Pa/mmHg = 96 558 Pa V - volume n - number of moles = mass / molar mass number of CS₂ moles = 2.0 g / 76.15 g/mol = 0.026 mol R - universal gas constant - 8.314 Jmol⁻¹K⁻¹ T - temperature in kelvin - 70 °C + 273 = 343 K substituting these values in the equation 96 558 Pa x V = 0.026 mol x 8.314 Jmol⁻¹K⁻¹ x 343 K V = 0.768 L the volume occupied is 0.768 L
