Arianna12345667 Arianna12345667
  • 09-06-2018
  • Mathematics
contestada

a3-b3=(a-b)(a2+an+b2) 64x6-27

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mkryukova19 mkryukova19
  • 09-06-2018
a³-b³=(a-b)(a²+ab+b²)

64x⁶ - 27

64 = 4³, 
x⁶ = (x²)³
27 = 3³

64x⁶ - 27 = 4³(x²)³ -3³ = (4x²)³ -3³.  Now, we can use a formula where a=4x², b=3

(4x²)³ -3³ = (4x² -3)((4x²)² +4x²*3 + 3²) =  (4x² -3)(16x⁴ +12x² + 9) 

Answer: 64x⁶ - 27=  (4x² -3)(16x⁴ +12x² + 9) 
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