horcio5284 horcio5284
  • 07-06-2018
  • Mathematics
contestada

What is the true solution to the logarithmic equation below? log4[log4(2x)]=1
a. x=2
b. x=8
c. x=64
d. x=128

Respuesta :

carlosego
carlosego carlosego
  • 18-06-2018
To solve this problem, you have:
 1. You have the following logarithmic expression log4[log4(2x)]=1, therefore:
 
log4[log4(2x)]=1
 4^log4[log4(2x)]=4^1
 2. By definition, a^log(x)=x, then:
 log4(2x)=4
 4^log4(2x)=4^4
 2x=4^4
 x=256/2
 x=128
 Therefore, the answer is the option d: d. x=128
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