chloebnett6493 chloebnett6493
  • 10-05-2018
  • Chemistry
contestada

Determine the molecular mass ratio of two gases whose rates of effusion have a ratio of 16 : 1.

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Dejanras
Dejanras Dejanras
  • 19-05-2018
Answer is: the molecular mass ratio of two gases is 1 : 256.
rate of effusion of gas1 : rate of effusion of gas = 16 : 1.
rate of effusion of gas1 = 1/√M(gas1).
rate of effusion of gas2 = 1/√M(gas2).
rate of effusion of gas1 = rate of effusion of gas2 
· 16.
1/√M(gas1) = 1/√M(gas2) · 16 /².
1/M(gas1) = 1/M(gas2) · 256.
M(gas1) · 256 = M(gas2).

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