Consider Pb²⁺ + 2 electrons → Pb. Use any data sheet to find which is anode and which is the half-cell, and the overall E⁰ cell is positive.
a) Anode: Pb²⁺, Cathode: Pb, E c⁰ell > 0
b) Anode: Pb, Cathode: Pb²⁺, E⁰ cell > 0
c) Anode: Pb, Cathode: Pb²⁺, E⁰ cell < 0
d) Anode: Pb²⁺, Cathode: Pb, E⁰ cell < 0