. Two circles touch externally at the point A. P is a point on the common tangent to the two circles at the point A. From P, tangents are drawn to touch the circles at X and Y respectively. (i) (ii) X Prove that |PX| = |PA|. Prove that |PX| = |PY|. A P Y

I figured out (i) but you will need the info from that to do (ii). please write the proof step by step.​