[tex]\text{Given that}~ x = 2,~ y = 3 ~ \text{and}~ z = -2\\\\\textbf{a)}\\\\2(x-y)=2(2-3) = 2(-1) = \boxed{-2}\\\\\textbf{b)}\\\\4x+3y-z = 4(2) +3(3) -(-2) = 8+9+2=\boxed{19}\\\\\textbf{c)}\\\\-2(3z+y) = -2[3(-2) +3] = -2(-6+3) = -2(-3) = \boxed{6}[/tex]
