Answer:
See below, please.
Step-by-step explanation:
[tex] \frac{ {(4a - 3b)}^{3} }{c + 5} \\ \ \\ = \frac{ {(4 \times ( - 2) - 3 \times ( - 3))}^{3} }{3 + 5} \\ = \frac{ {(( - 8) - ( - 9))}^{3} }{8} \\ = \frac{ {( - 8 + 9)}^{3} }{8} \\ = \frac{ {1}^{3} }{8} \\ = \frac{1}{8} [/tex]
