Answer:
504 cm²
Step-by-step explanation:
Let the length and the width of the rectangle be L cm and W cm respectively.
Perimeter= 2(L +W)
2(L +W)= 108
L +W= 108 ÷2
L +W= 54
L= 54 -W -----(1)
[tex] \frac{L}{W} = \frac{7}{2} [/tex]
Cross multiply:
2L= 7W -----(2)
Substitute (1) into (2):
2(54 -W)= 7W
Expand:
108 -2W= 7W
+2W on both sides:
9W= 108
Divide both sides by 9:
W= 108 ÷9
W= 12
Substitute W= 12 into (1):
L= 54 -12
L= 42
Area of rectangle
= length ×width
= LW
= 42(12)
= 504 cm²
