Answer:
{x | x ∈ R, 4,-1}
Step-by-step explanation:
[tex]y=x^2-3x-4[/tex]
[tex]y=x^2+x-4x-4[/tex]
[tex]y=(x^2+x)+(-4x-4)[/tex]
[tex]y=x(x+1)+(-4)(x+1)[/tex] Distributive property
[tex]y=(x+(-4))(x+1)[/tex] Distributive Property
[tex]y=(x-4)(x+1)[/tex]
set y to 0
[tex]0=(x-4)(x+1)[/tex]
set the factors to 0
[tex]0=x-4; 0=x+1[/tex]
[tex]4=x; -1=x[/tex]
