myrkardgzz myrkardgzz
  • 11-11-2020
  • Mathematics
contestada

Solve Sec(2x)-4=0 for the first two positive solutions. thanks!

Respuesta :

LammettHash
LammettHash LammettHash
  • 11-11-2020

sec(2x) - 4 = 0

sec(2x) = 4

1 / cos(2x) = 4

cos(2x) = 1/4

2x = cos⁻¹(1/4) + 2nπ   or   2x = -cos⁻¹(1/4) + 2nπ

(where n is any integer)

x = 1/2 cos⁻¹(1/4) + nπ   or   x = -1/2 cos⁻¹(1/4) + nπ

The first two positive solutions occur for n = 0 in the first family of solutions, and for n = 1 in the second family, so

x = 1/2 cos⁻¹(1/4)   or   x = π - 1/2 cos⁻¹(1/4)

x ≈ 0.659   or   x ≈ 2.483

Answer Link

Otras preguntas

A typical high school student consumes 67.5 pounds of sugar per year. As part of a new nutrition plan, each member of a track team plans to lower the sugar he o
Mention the location of the kidney in our body.
Describe how that koan relates to the practice of Zen Buddhism
what is 5 divide by zero? but the answer is not zero???????????????????????????????????????????????????????????????????????????
Definition of non-conventional energy sources.
Are all metals acidic in nature and all non-metals basic? and what is the nature of their oxides?
what are capillaries
What does vena cava transport?
Which part of the nephron is connected to the ureters. (excretion)
How to generate electricity from biogas?