Valishati Valishati

09-04-2020
Mathematics

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Over which interval does a valid solution exist for dy/dx=−2/(x^(3))+2e^(2x−2)?

Over which interval does a valid solution exist for dydx2x32e2x2 class=

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amna04352 amna04352

09-04-2020

Answer:

D

Step-by-step explanation:

-2×(x^-3) + 2e^(2x-2) = dy/dx

Integrate for y

y = -2×(x^-2)÷-2 + 2[e^(2x-2) ÷ 2] + c

y = 1/x² + e^(2x-2) + c

y is undefined only at x² = 0

Because x² is in the denominator

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