Plug the values for a, b, and c in the expression given.
[tex]\frac{1}{7}[\frac{16}{-4}+8(3-\sqrt{25})^{2}]=\frac{1}{7}[\frac{16}{-4}+8(3-5)^{2}]=\frac{1}{7}[-4+8(-2)^{2}]= \frac{1}{7}[-4+8(4)]=\frac{1}{7}{[-4+32]=\frac{1}{7}[28]=4[/tex]
Answer:
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Step-but you should y-step explanation:
