Answer:
[tex]\large\boxed{\dfrac{2}{3(4x+9)}=\dfrac{2}{12x+27}}[/tex]
Step-by-step explanation:
"two over three (4x + 9)":
[tex]\dfrac{2}{3(4x+9)}[/tex]
use the distributive property a(b+c) = ab + ac
[tex]=\dfrac{2}{(3)(4x)+(3)(9)}=\dfrac{2}{12x+27}[/tex]
