jovanisantana5 jovanisantana5
  • 08-06-2018
  • Mathematics
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The hypotenuse of a 45°-45°-90° triangle measures 10 sqrt 5 in. What is the length of one leg of the triangle?

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tdpuppies14
tdpuppies14 tdpuppies14
  • 08-06-2018
There is this specific ratio for 45-45-90 triangles where the length of the hypotenuse is radical 2 times as long as a leg. With this in mind, we can create an equation where the length of one leg is represented with the variable x.

x[tex] \sqrt{2} [/tex] = 10[tex] \sqrt{5} [/tex] 
divide both sides by [tex] \sqrt{2} [/tex] 
x = 10[tex] \sqrt{5} [/tex] / [tex] \sqrt{2} [/tex] 
x = 10[tex] \sqrt{10} [/tex] /2
x = 5[tex] \sqrt{10} [/tex] 

The length of one leg is 5[tex] \sqrt{10} [/tex] 
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